what is derivative of 3x^2 divided by 6x^3 + 4x^2 plz?

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what is derivative of 3x^2 divided by 6x^3 + 4x^2 plz?

2007-01-29 17:47:57 · 4 answers · asked by alferido a 1 in Science & Mathematics ➔ Mathematics

4 answers

3x^2/6x^3 + 4x^2
=3x^2/ 2x^2(3x+2)
=1.5/(3x+2)
now take the derivative -1.5*3/(3x+2)^2
= -9/2(3x+2)^2

2007-01-29 19:40:45 · answer #1 · answered by Pradeep Chelani 2 · 0⤊ 0⤋

[(6x)(6x^3 + 4x^2)-(18x^2+8x)(3x^2) ] / [(6x^3 + 4x^2)^2]

2007-01-30 02:27:51 · answer #2 · answered by iyiogrenci 6 · 0⤊ 0⤋

use the quotient rule.
It looks like this
f(x)/g(x)=
g(x)f'(x)-f(x)g'(x)
---------------------(divide by)
[g(x)]^2

f(x) will equal 3x^2 and
g(x) will equal 6x^3+4x^2
f'(x) will equal 6x and
g'(x) will equal 18x^2+8x

the rest is just plugging it in and simplifying
hope it helps

2007-01-30 01:56:01 · answer #3 · answered by Elizabeth 2 · 0⤊ 0⤋

-9/2(3x+2)^2

2007-01-30 01:54:29 · answer #4 · answered by Joy C 1 · 0⤊ 0⤋