The solution to this equation => T = 1 / 1 - SQRT(0.8)^2 <== is T=167
I can't come up with a way to solve for that answer. Would appreciate someone showing me a step-by-step solution to the equation.
2007-01-29 17:47:11 · 4 answers · asked by Chug-a-Lug 7 in Science & Mathematics ➔ Mathematics
You may need to add more parentheses to your equation, because the way it reads now, T = 5.
T= 1 / 1 - sqrt(0.8)^2
=1 / 1 - 0.8 (the square root of 0.8 squared is 0.8)
=1 / 0.2
=5
2007-01-29 18:02:36 · answer #1 · answered by birdr 2 · 0⤊ 0⤋
make sure about the Q.........
T = 1 / 1 - SQRT(0.8)^2
about the POWER of 2....
is it on the SQRT or on the whole equation????
Start a new Q... with the correct equation....
I'll be there..
:)
2007-01-30 02:04:49 · answer #2 · answered by aldandooon 1 · 0⤊ 0⤋
I don't know. The SQRT(0.8)^2 would just be 0.8, wouldn't it because the sqrt and ^2 cancel each other out.
2007-01-30 02:00:58 · answer #3 · answered by Elizabeth 2 · 0⤊ 0⤋
There is something missing here.
1/0.2 = 5, and 1/1.8 = 0.555556
167 is prime, so it can only be the reciprocal of 1/167
If 1 - x = 1/167, x = 1 - 1/167 = 166/167
2007-01-30 02:24:20 · answer #4 · answered by Helmut 7 · 0⤊ 0⤋