How many grams of Na are in 385 ml of a .75 M Na2CO3 solution??
2007-01-29 17:24:13 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
First, multiply the Molarity by 0.385 LITERS of volume (note the conversion already) you should get 0.28875 moles of sodium carbonate.
But there are 2 sodium atoms so this gives 2x0.28875 = 0.5775 Na
And since the atomic mass of sodium is 23 g/mole of Na, then the number of grams is = 13 g ( note sig fig)
2007-01-29 17:35:56 · answer #1 · answered by Aldo 5 · 0⤊ 0⤋
I don't have a periodic table in front of me but I can tell you the steps. Find out how much one mole of Na2CO3 is (Na+Na+C+O+O+O= molar mass) then multiple by .75 to get the .75M solution, then determind how many moles are in 385ml. Then you need to divide the (g) of Na by the whole .75M NaCO3 to determine the percentage of Na in .75M NaCO3. Then divide again by that number.
2007-01-30 01:34:22 · answer #2 · answered by Anonymous · 0⤊ 1⤋