How far would the person walk due north and due east to arrive at the same location?
-Lets see how fast can you can do this one guys
2007-01-29 16:37:03 · 2 answers · asked by cosmo 1 in Science & Mathematics ➔ Physics
OK. Start with an x/y axis. Draw a line originating at point (0,0) and extending 3.80km at 25 degrees.
We need to determine the values for x and y. x would be the distance walked due east and y would be the distance walked north.
Use trigonometric functions of right triangles (which is what this is if you draw it out and add a line extending parallel from the x axis to your 25 degree line at any point).
sin 25 degree angle = y/3.80
sin 25 degrees = 0.423
0.423 = y/3.80
solve for y ----> y = 1.6
Now we can find x. We could use the cos of 25 degrees or
x^2 + y^2 = r^2
x^2 + (1.6)^2 = (3.80)^2
x^2 + 2.56 = 14.44 -------> solve for x ----> x = 3.4
x^2 = 11.88 ----> x = 3.4
So if you walk due north then due east it would be
y + x = 1.6 + 3.4 = 5km
2007-01-29 17:02:54 · answer #1 · answered by RR 2 · 0⤊ 0⤋
sin(25)*3.8+cos(25)*3.8
1.6 km E
3.44 km N
j
2007-01-29 16:58:32 · answer #2 · answered by odu83 7 · 0⤊ 0⤋