I need to get two answers for x at the end
2007-01-29 16:08:04 · 5 answers · asked by ashleygiardina 1 in Science & Mathematics ➔ Mathematics
The factorization of your polynomial is:
(2x + 23)(x - 3)
It's not really too hard, because the only choices for 2 are 1 × 2, and the only choices for 69 are 1 × 69 (which clearly doesn't work) and 3 × 23.
2007-01-29 16:15:43 · answer #1 · answered by Jim Burnell 6 · 1⤊ 0⤋
let
_ * _ = -138, -138 comes from 2*(-69)
_ + _ = 17 ; where it is
23 * -6 =-138
23 + -6 = 17
2x^2 - 6x + 23x - 69 =0
2x( x-3) + 23(x-3) =0
(2x+23)(x-3) =0
x=-23/2 = -11.5 or x=3
2007-01-29 17:57:44 · answer #2 · answered by cute_gurl 1 · 0⤊ 1⤋
the the quadratic equation:
x = -b +- {b^2 - 4ac} / 2a, where "{" denotes square root
Therefore,
x = -17 +- {289 +61} / 4
x= -17 +- {350} / 4
x= -17 +- {25 * 14} / 4
Therefore:
x= -17 + 5{14} / 4 or x= -17 - 5{14} / 4
2007-01-29 16:18:29 · answer #3 · answered by Anonymous · 0⤊ 1⤋
That is not an Equation since it has no value on the other side of the "=" equals sign. The possible values of X are infinite in your "equation".
2007-01-29 16:18:34 · answer #4 · answered by JD 4 · 0⤊ 1⤋
that is not an equation, it's a polynomial or an expression.
2007-01-29 16:15:57 · answer #5 · answered by Theta40 7 · 0⤊ 1⤋