how to solve equations with negative exponents?

Question

a-2
------ then that in parentheses times negative 2
b-3

-2 and -3 are exponents

Answer 1

Whenever a numerator is having a negative exponent take it to the denominator changing the sign of the exponent.similarly,if the is a denominator with a negative sign,take it to the numerator reversing the sign
For example a^-3=1/a^3 or,12/b^-5=12*b^5 or c^-8=1/c^8
Now,let us try to solve the problems sent by you
(a^-2)/(b^-3)=(1/a^2)(1/b^3)
=(1/a^2)(b^3/1)
=b^3/a^2

Answer 2

any negative exponent simply means you take the reciprocal of that term

ie. (x^-2) or x squared
is the same as (1/x^2) or 1 over x squared

Answer 3

a^-2 = 1/a². So the fraction becomes b^3/a^2. The rest should be self-evident.

Answer 4

x^ -a million = a million/x likewise x^ -2 = a million/x² So enable u = a million/x change: u² + 8u - 9 = 0 component: (u + 9)(u - a million) = 0 so u = -9 and u = a million keep in mind that u = a million/x -9 = a million/x for this reason, x = -a million/9 and a million = a million/x, x = a million