A cubic decimeter (1.0 x10^-3 m^3) of steel is submerged in water:?

Question

A. What is the magnitude of the boyant force acting upon it?
B. What is the apparent weight of the steel once submerged in water ( D=9000 kg/m^3)
I need to know how you did this because it is a example for my test tomorrow! another problem just like this will be used but of course with different numbers! Thanks!

Answer 1

A cubic decimeter is one liter.

A. The buoyant force will be equal to the weight of one liter of water so 1kg -> 9.8N

B. The weight of the steel is 9kg/l so the apparent weight will be 9-1 = 8kg/l or 8000 kg/m^3