Parallel Plates~Capacitor?

What is the capacitance of two square parallel plates 6.5 cm on a side that are separated by 1.6 mm of rubber? K (dielectric constant) of rubber is 2.8.

2007-01-29 14:18:14 · 0 answers · asked by Anonymous in Science & Mathematics ➔ Physics

0 answers

C=k*e0*A/d

e0 = permittivity of vacuum, k= dielectric constant, A = plate area d = plate separation.

e0 = 8.9*10^-12 F/m

2007-01-29 14:24:54 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋

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