Solve 4w-(w+3)=3(w-1)?

Question

I know this is trivial but I honestly need help

Answer 1

First: eliminate parenthesis-use distribution by multiplying & distributing the negative sign & outer term with the terms in parenthesis...

4w - w - 3 = 3(w) - 3(1)

4w - w - 3 = 3w - 3

3w - 3 = 3w - 3

Sec: combine "like" terms > add "3" to both sides...

3w - 3 + 3 = 3w - 3 + 3

3w = 3w

Third: since both sides equal each other, the solution is...there is an infinite amount of solutions.

Answer 2

I prefer to rewrite a subtraction that needs to be distributed as a negative one.

4w -1(w + 3) = 3(w - 1)

Distribute the -1 and the 3.
4w -w -3 = 3w - 3

Collect like terms on the left side.
3w - 3 = 3w - 3

And at this point it's pretty clear you have an identity since the left side is equal to the right side. No matter what value of w you substitute the equation will always work.

Answer 3

i'm assuming you have: [(4w-a million)/(3w+6)] - [(w-a million)/3] = [(w-a million)/(w+2)] So....on account that (3w+6) = 3(w+2), then: (4w-a million)/3(w+2) - (w-a million)/3 computes to: [(4w-a million) - (w-a million)(w+2)]/3(w+2) = (w-a million)/(w+2) The (w+2) interior the denominator cancels out on the two area of the equality sign, leaving you with [(4w-a million) - (w-a million)(w+2)]/3 = (w-a million) bypass-multiplying: (4w-a million) - (w-a million)(w+2) = 3w-3 hence: (4w-a million) - (w^2+w-2) = 3w-3 4w - a million - w^2 -w +2 - 3w +3 = 0 4 - w^2 = 0 (2+w)(2-w) = 0 So w = +/- 2

Answer 4

4w-w-3 = 3w-3
3w-3 = 3w-3
0 = 0

This is a weird equation. It is actually true for all values of w. Is your teacher playing a joke on you?

Answer 5

w=4 or -4

Answer 6

4w^2-15w=-3

Answer 7

its basic algebra but i still think its hard W=3 i believe but im not positive sorry i just got done solving fractions in my hs math class