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I just want to make sure I'm doing this correctly... Here's the problem:

Find the length of the arc intercepted by angle "Θ" on a circle with the radius "r".

r = 14cm
Θ = 2.5 radians

2007-01-29 12:21:25 · 4 answers · asked by Shawn 1 in Science & Mathematics Mathematics

4 answers

find the length of the circumference of the circle:

2*pi*r = 2*(PI)*(14)

now you know that the whole circle is 2*PI radians...
since you only have a wedge of a circle that has 2.5 radians, you can take the fraction of it:
2.5 / 2*(PI)

Then multiply it with the total circumference of the circle:

2.5 / 2*PI * 2*PI*14 = 2.5 * 14 = 35 cm

Then you get the answer as the length of the arc... 35cm

2007-01-29 12:29:25 · answer #1 · answered by wootness 2 · 0 0

S = length of arc = rØ

substitute and you get 35 cm.

2007-01-29 20:26:06 · answer #2 · answered by Aldo 5 · 0 0

around the whole circle the length is 2 pi r

so for angle A it must be (A/(2 pi)) 2 pi r =A r

2007-01-29 20:27:04 · answer #3 · answered by mounthood13 1 · 0 0

length = r*theta = 14cm(2.5 rdn) = 35 cm

2007-01-29 20:26:05 · answer #4 · answered by kellenraid 6 · 0 0

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