How do I Factor the Polynomial 3x^3 + 2x^2 – 7x + 2 completely?

Answer 1

group it
(3x^3+2x^2) - (7x-2) (i changed it to minus 2 because you have to take into acount distributing the minus sign)

it would end up being
x^2(3x+2) - (7x -2)
x= 0, -2/3, 2-7

Answer 2

The numerical digit of the expression is 2,which has factors of +1,-1,+2and -2
Now if you put these values for x ,one by one,you shall find that if x=1,the value of the expression becomes zero
Therefore x-1 is a factor of the expression
Given exp=3x^2(x-1)+5x(x-1)-2(x-1)
=(x-1)(3x^2+5x-2)
=(x-1) (3x^2+6x-x-2)
=(x-1){3x(x+2)-1(x+2)}
=(x+1)(x+2)(3x-1)

Answer 3

Dunno, my guess would be

x^2(3x+2) - (7x+2)