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7k^2+10k-100=2k^2+55 Please help solve it.?
Can you show me how to do it in fractions step by step please i want to learn.
Explain it to me like if i was a retard please.

2007-01-29 11:38:28 · 3 answers · asked by Ballerina 5 in Science & Mathematics Mathematics

3 answers

7k² + 10k - 100 = 2k² + 55

Bring everything to the left side by subtracting:

7k² + 10k - 100 - 2k² - 55 = 2k² + 55 - 2k² - 55

7k² - 2k² + 10k - 100 - 55 = 0

Simplify:

5k² + 10k - 155 = 0

Factor out a 5:

5(k² + 2k - 31) = 0

Divide both sides by 5:

k² + 2k - 31 = 0

Use quadratic formula.

k = (-2 ± √(2² - 4 × 1 × (-31))/(2 × 1)

k = (-2 ± √128)/2

k = (-2 ± √64√2)/2

k = (-2 ± 8√2)/2

k = -1 ± 4√2

2007-01-29 11:43:43 · answer #1 · answered by Jim Burnell 6 · 0 1

7k^2 + 10k - 100 = 2k^2 + 55

7k^2 -2k^2 + 10k - 100 - 55 = 2k^2 + 55 -2k^2 - 55

5k^2 + 10 k - 155 = 0

Factor out 5

k^2 + 2 k - 31 = 0

using formula in link below the Quadratic formula

x = -2 +/- s/r 128 s/r =square root
----------------
2


x = -1 + 4 s/r 2 , -1 - 4 s/r 2

x = -1 + 5.66 = 4.66 and x = -1 - 5.66 = - 6.66

2007-01-29 20:01:50 · answer #2 · answered by romeo_1595 2 · 0 0

7k^2+10k-100=2k^2+55
=>7k^2-2k^2+10k=55+100
=> 5k^2+10k=155
=> 2k^2+2k=31 [diviving all the terms by 5]
=> k^2+k=31/2
=>(k)^2+2*k*1/2+(1/2)^2=31/2+1/4
=>(k+1/2)^2=63/4
=>k+1/2=+-sqrt63/2
=>k= -1/2+-sqrt63/2=(1+-sqrt63)/2

2007-01-29 20:00:15 · answer #3 · answered by alpha 7 · 0 1

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