Standard Form equation for circle: (x-h)^2 + (y-k)^2 =r^2
where center = (h,k) and r =radius
Find the standard form of the equation for the circle:
x^2 -10x +y^2 + 6y = -9
2007-01-29 11:32:15 · 4 answers · asked by jenny 6 in Science & Mathematics ➔ Mathematics
Complete the square.
x² - 10x + y² + 6y = -9
(x² - 10x +25) + (y² + 6y + 9) = -9 + 25 + 9
(x - 5)² + (y + 3)² = 25
It is a circle with center (5,-3) and radius 5.
2007-01-29 11:36:44 · answer #1 · answered by Northstar 7 · 2⤊ 0⤋
Complete the square
x^2 - 10x + (10/2)^2 + y^2 + 6y + (6/2)^2 = -9 + (10/2)^2 + (6/2)^2
x^2 - 10x + 25 + y^2 + 6y + 9 = -9 + 25 + 9
(x-5)^2 + (y+3)^2 = 25
(h,k) = (5,-3)
r = 5
2007-01-29 19:38:48 · answer #2 · answered by MsMath 7 · 1⤊ 1⤋
x2-10x+25+y2+6y+9=-9+25+9
(x-5)2+(y+3)2=25
2007-01-29 19:38:22 · answer #3 · answered by MS32291 4 · 1⤊ 0⤋
Addition to Northstar's answer
(x -5)^2 + (y + 3)^2 = 5^2
and continue
2007-01-29 19:39:50 · answer #4 · answered by Sheen 4 · 1⤊ 0⤋