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you are 27m from the bus.
you run your max speed of 12 m/s and at that moment, the bus begins to pull away.
the bus has a constant acceleration of 1.11 (m/s^2) and continues to accelerate until it reaches its speed of 15m/s when it travels at a constant speed.

how long does it take the bus to reach your running speed?

write an equation for your position vs. time and one for the position vs. time of the bus...

ANY help would be REALLY appreciated...

2007-01-29 10:24:21 · 2 answers · asked by kacee 1 in Science & Mathematics Physics

2 answers

If what you're trying to figure out is "how long does it take the bus to reach your running speed", then where you are is irrelevant; you want to find out how long it takes the bus to get to 12m/s. (1/2)at^2+vt+d=0 applies.
If you're trying to figure out when you catch the bus, the same equation still applies with a=1.11, v=-12, and d=-27.

2007-01-29 10:52:14 · answer #1 · answered by Anonymous · 0 0

We don't do homework here.

Seriously.

I did my HS physics homework in 1980.

2007-01-29 18:32:02 · answer #2 · answered by geek49203 6 · 0 0

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