answer this please explain?

Question

margie is twice as old as jenny and sarah is twivce as old as margie. their combined ages total 133 years. how old is each person?

Answer 1

jennys age = x
margies age = 2x
sarahs age = 4x
x + 2x + 4x = 133
133/7 = x
x = 19

Jenny is 19
Margie is 38
Sarah is 76

Answer 2

Let Jenny be x years
Margie will then be 2x years
Sarah will then be 4x years
4x + 2x + x = 133
7x = 133
x = 19
So Jenny is 19, Margie is 38 and Sarah is 76
Check: total is 133

Answer 3

jenny = x
margie = 2x
sarah = 4x
x + 2x + 4x = 133
7x = 133
x=133/7
x = 19
then jennys 19
margie is 2(19) =38
and sarah 4(19)=76

Answer 4

m= marge
j= jenny
s= sarah

m=2j
s=2m
s=4j

m+j+s=133
substituting for m and s

2j+j+4J=133 or 7j= 133 or j= 19
if j= 19 and m= 2j then m= 38
If j= 19 and s= 4j then s= 76

check: 19+38+76= 133

Answer 5

Jane=J; Margie=M; Sarah=S
then J is 4 times smaller then S and twice small than M
J+M+S=133
J+2J+4J=133
7J=133
J=19

Jane is 19
Margie is 38
Sarah is 76

I think I am right

Answer 6

let's say that x is Jenny's age.

M - 2x
S - 2m
s = 2 (2x)
s = 4x
S + M + x = 133
4x + 2x + x = 133
7x = 133
x = 19
M = 38
S = 76

Answer 7

m=2j
s=2m
m+s+j=133