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i need to kno.. how do u graph x/2 +y/3 =1

2007-01-29 08:35:51 · 5 answers · asked by luciouzz_prmami 1 in Science & Mathematics Mathematics

5 answers

It's easiest to graph a linear equation in slope-intercept form. So multiple both sides of this equation by 3 to get 3x/2 + y = 3 ==> y = -3x/2 + 3. The y-intercept is 3, so put (0, 3) on your graph. The slope is -3/2, so draw a line with that slope (go 3 units down and two to the right, and then continue that line) starting from the point you have.

When working with a linear equation in slope-intercept form, the equation y = mx + b means that the line has a slope of m and a y-intercept of b. What the y-intercept means is that the line crosses the y-axis at the point (0, b).

2007-01-29 08:40:41 · answer #1 · answered by DavidK93 7 · 2 1

Easy. This is an equation of a Straight line in TWO-intercept form. It is a neat form of the line. Hardly ever discussed in classes.

This means you have an x intercept of 2 and a y intercept of 3. Plot these points and TADA. No need to calculate.

So, you have a straight line mostly in the first quadrant with a NEGATIVE slope.

You do not have to do all what all previous responders told you. Waste of time because it is in two intercept form already.

2007-01-29 16:44:40 · answer #2 · answered by Aldo 5 · 0 1

Solve for y

y/3=-x/2+1
y=-3/2 x +3

The y-intercept is 3 so put a point there.

The slope is negative means down 3 and to the right 2 from your y-intercept.

Then connect the two points with a line.

2007-01-29 16:43:37 · answer #3 · answered by Professor Maddie 4 · 0 2

You can solve for y:

y/3 = -x/2 + 1

y = -3x/2 + 3

then graph it using the slope-intercept method.

2007-01-29 16:41:41 · answer #4 · answered by bag o' hot air 2 · 0 2

x/2 +y/3 =1
3x/2 + y = 3
y = -1.5x + 3
Now you know.

Th

2007-01-29 16:42:35 · answer #5 · answered by Thermo 6 · 0 2

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