2007-01-29 08:35:11 · 7 answers · asked by jamaicangirl 1 in Science & Mathematics ➔ Mathematics
please explain
2007-01-29 08:42:00 · update #1
You're finding three consecutive numbers, so
(x) + (x+1) + (x+2) = 57
Combine like terms, so
3x + 3 = 57
Subtract 3 from both sides, so
3x = 54
Divide both sides by three, so
x = 18
Plug 18 back into the beginning problem, so
(18) + (18+1) + (18+2) = 57
18 + 19 + 20 = 57
So your three consecutive numbers are 18, 19, and 20.
2007-01-29 08:42:27 · answer #1 · answered by ensign183 5 · 1⤊ 0⤋
18 19 20
2007-01-29 08:42:25 · answer #2 · answered by Anonymous · 0⤊ 0⤋
57 divided by 3 is 19. The two odd numbers either side of that, as the difference from 19, as 21 - 2 = 19 and 17 + 2 = 19.
2016-03-29 08:33:02 · answer #3 · answered by Michele 4 · 0⤊ 0⤋
18, 19, 20
2007-01-29 09:06:43 · answer #4 · answered by ramshi 4 · 0⤊ 0⤋
n+(n+1)+(n+2)=57
2007-01-29 08:39:53 · answer #5 · answered by Professor Maddie 4 · 0⤊ 0⤋
x + (x+1) + (x+2) = 57
3x = 54
x = 18
The numbers are 18, 19 and 20.
Th
2007-01-29 08:46:37 · answer #6 · answered by Thermo 6 · 0⤊ 0⤋
(n-1) + n + (n+1) = 57
3n = 57
n = 19
18,19,20
2007-01-29 08:42:36 · answer #7 · answered by bequalming 5 · 0⤊ 0⤋