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Given the following data:


2Mg + O2 → 2MgO Delta = −1204


MgO + H2O → Mg(OH)2 Delta H = −37


2H2O → 2H2 + O2 Delta H = +572 kJ

2007-01-29 07:55:18 · 1 answers · asked by simonkf2002 1 in Science & Mathematics Chemistry

1 answers

To half of the first, add the second and subtract half of the third.

2007-01-29 08:35:23 · answer #1 · answered by Gervald F 7 · 0 0

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