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plz help me with these math problems
a) find the points of intersection of the live x-2y=5 and the hyperbola xy=88
b) find the small integer of such that f(a)=o and then factorize f(x)=1ox^3 + 104x^2 + 34x - 60
thaaaanx

2007-01-29 06:03:51 · 4 answers · asked by thelittle_angel1327 2 in Science & Mathematics Mathematics

4 answers

xy= 88 --> x = 88/y
88/y -2y =5
88 -2y^2=5y
2y^2 +5y -88 = 0
y= [-5 +/-(sqrt(25-4*2(-88))]/2
y= (-5 +/- 27)/2
y = -16 or y = 11
So x = 88/y= -5.5 or 8
The points of intersection are (8,11) and (-5.5, -16)

-1 is the smallest integer making f(x) = 0 so (x+1) is a factor.
f(x)= (x+1)(10x^2+94x-60)
= (x+1)(x+10)(10x-6)

2007-01-29 07:08:58 · answer #1 · answered by ironduke8159 7 · 0 0

a) first change the formats to y =mx + b because it's easier to work with.
x - 2y = 5
to chance this to y =mx + b format first subtract x from both sides
-2y = 5 - x
now divide both sides by -2
y = (5 - x)/2
now the other equations xy = 88
divide both sides by x so you have
y = 88/x
Now to figure out where they intersect set the two equations equal to each other... that is
(5 - x)/2 = 88/x
Now what you want to do is get all the like terms on one side of the equations so to get ride of the two multiply both sides by 2
(5 - x) = 176/x
now mulitply both sides by x
(5 - x)x = 176
then distribute the x and you get
5x - x^2 = 176
now subtract 176 from both sides to get
-x^2 + 5x - 176 = 0
here what you do is use the quadratic formula... sorry i have to go my class is starting but email me or im me if you don't figure it out and you need more information. Good Luck

2007-01-29 06:23:00 · answer #2 · answered by PaRtaP 1 · 0 1

x-2y=5 xy =88 from the first x= 5+2y so by substitution

(5+2y)*y =88 so 2y^2 +5y -88=0 y= ((-5+-sqrt(377))/4

For each y you find x going to x= 5+2y
b)f(-1)=0 so factorizing f(x)= (x+1)(10x^2+ 94x-60)

2007-01-29 07:06:02 · answer #3 · answered by santmann2002 7 · 0 1

a) x=2y+5

(2y+5)(y)=88
2y²+5y-88=0
solve for y, subtitute to find the x values that correspond.

b) just looks ugly. forget it. :o)

2007-01-29 06:17:42 · answer #4 · answered by bequalming 5 · 0 0

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