Question: state whether each of the following substances is likely to be very soluble in water. Explain!
(a) lithium nitrate
(b) glycine, H2NCH2COOH
(c) Pentane
(d) Ethylene glycol, HOCH2CH2OH
My approach:
this is a very tough question for me b/c i didnt cover it that much. please give me an explanation of why or why not any of these chemicals are soluble. THANKS! (i award best answers)
2007-01-29 05:50:46 · 3 answers · asked by Jimmy 3 in Science & Mathematics ➔ Chemistry
* Lithium Nitrate - Soluble in water. Because it is ionic. It can be easily ionizes in water.
* Glycine - Soluble because of it's -COOH group.
* Pentane - Insoluble in water. The type of intermolecular forces between water molecules is 'hydrogen bonds' but the type of intermolecular forces between pentane molecules is 'Van der Waal bonds'. So there can not be a strong intermolecular force between a water molecule and a pentane molecule. Thus, pentane is insoluble in water.
* Ethylene glycol - Soluble. As it is a diol, it can form hydrogen bonds with water molecules.
2007-01-29 06:41:17 · answer #1 · answered by ශාකුන්තල | shaakunthala 3 · 0⤊ 0⤋
a) lithium nitrate should be very soluble since LiNO3 ia a salt strong electrolyte
B) glycine is an aminoacid so an electrolyte and should be soluble in water
C) pentane is a non polar molecule. No affinity with water insoluble
d) ethleglycol has 2 polar groups OH . So ,it should be soluble in water
2007-01-29 06:33:31 · answer #2 · answered by maussy 7 · 0⤊ 0⤋
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it's not right should be 80% of 38.2 g 0.8 x 38.2 = 30.6 g FW Na2S = 66 g/mole 5g/66 =0.076 moles /0.4L = 0.19M
2016-04-03 03:44:21 · answer #3 · answered by Anonymous · 0⤊ 0⤋