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2007-01-29 05:46:10 · 9 answers · asked by momoftwins1986 1 in Science & Mathematics Mathematics

9 answers

Take each part and divide it separately.

Separate the coefficients (the 50 and the 10), the p's (p^9 and p), and the q's (q^5 and q^2). Now do each part separately.

50/10 = 5
p^9/p = p^8. (If that doesn't make sense, think of it this way. You've got 9 p's on top of the fraction and 1 p on bottom. The 1 p on bottom will cancel out one of the p's on top' leaving 8 p's, or p^8.)
q^5/q2 = q ^3. (Same reasoning as the p's. You've got 5 q's on top and 2 on bottom. The 2 on bottom will cancel out 2 of the q's on top, leaving q^3)

So final answer is 5p^8q^3.

Good luck with the twins.

2007-01-29 06:19:43 · answer #1 · answered by Pythagoras 7 · 0 1

50p^9q^5/10pq^2 = (50/10)(p^9/p)(q^5/q^2) =5 p^8 q^3 Answer.

2007-01-29 14:00:38 · answer #2 · answered by Anonymous · 0 0

(50p^9q^5)/(10pq^2)

First: divide the coefficients...

50/10 = 5

Sec: divide the "p" variables...

p^9/p

*When you have the same base "x" > subtract exponents...

p^8

Third: divide the "q" variables...

q^5/q^2

= q^3

*Last, combine the term & variables together...

= 5p^8q^3

2007-01-29 14:37:25 · answer #3 · answered by ♪♥Annie♥♪ 6 · 0 0

50/10 =5, p^9/p=p^8 and q^5/q^2 = q3

so the result is 10p^8q^3

2007-01-29 14:18:26 · answer #4 · answered by maussy 7 · 0 0

50p^9q^5/10pq² =
5p^8q³
><

2007-01-29 16:04:43 · answer #5 · answered by aeiou 7 · 0 0

= (50/10) (p^9/p)(q^5/q^2)

=5 (p^(9-1)) (q^(5-2))

=5p^8q^3

2007-01-29 13:56:31 · answer #6 · answered by bequalming 5 · 0 0

50p^9q^5
_______
10pq^2


5p^8q^3

2007-01-29 13:53:21 · answer #7 · answered by      7 · 0 0

5p^8q^3

2007-01-29 14:12:27 · answer #8 · answered by shamu 2 · 0 1

10p^8q^3

2007-01-29 13:51:44 · answer #9 · answered by bruinfan 7 · 0 1

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