Take each part and divide it separately.
Separate the coefficients (the 50 and the 10), the p's (p^9 and p), and the q's (q^5 and q^2). Now do each part separately.
50/10 = 5
p^9/p = p^8. (If that doesn't make sense, think of it this way. You've got 9 p's on top of the fraction and 1 p on bottom. The 1 p on bottom will cancel out one of the p's on top' leaving 8 p's, or p^8.)
q^5/q2 = q ^3. (Same reasoning as the p's. You've got 5 q's on top and 2 on bottom. The 2 on bottom will cancel out 2 of the q's on top, leaving q^3)
So final answer is 5p^8q^3.
Good luck with the twins.
2007-01-29 06:19:43
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answer #1
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answered by Pythagoras 7
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50p^9q^5/10pq^2 = (50/10)(p^9/p)(q^5/q^2) =5 p^8 q^3 Answer.
2007-01-29 14:00:38
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answer #2
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answered by Anonymous
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(50p^9q^5)/(10pq^2)
First: divide the coefficients...
50/10 = 5
Sec: divide the "p" variables...
p^9/p
*When you have the same base "x" > subtract exponents...
p^8
Third: divide the "q" variables...
q^5/q^2
= q^3
*Last, combine the term & variables together...
= 5p^8q^3
2007-01-29 14:37:25
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answer #3
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answered by ♪♥Annie♥♪ 6
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50/10 =5, p^9/p=p^8 and q^5/q^2 = q3
so the result is 10p^8q^3
2007-01-29 14:18:26
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answer #4
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answered by maussy 7
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50p^9q^5/10pq² =
5p^8q³
><
2007-01-29 16:04:43
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answer #5
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answered by aeiou 7
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= (50/10) (p^9/p)(q^5/q^2)
=5 (p^(9-1)) (q^(5-2))
=5p^8q^3
2007-01-29 13:56:31
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answer #6
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answered by bequalming 5
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50p^9q^5
_______
10pq^2
5p^8q^3
2007-01-29 13:53:21
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answer #7
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answered by 7
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5p^8q^3
2007-01-29 14:12:27
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answer #8
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answered by shamu 2
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10p^8q^3
2007-01-29 13:51:44
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answer #9
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answered by bruinfan 7
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