The roots are:
1) +/- 1/2
2) +/- 2
3) +/- 3/2
4) +/- 1
2007-01-29 05:25:50 · 5 answers · asked by Random G 3 in Science & Mathematics ➔ Mathematics
x = +3/2 and x = 1
2x² - 5x + 3 = 0
{-b ± √[-b² - 4ac]} / 2a = 0
{-(-5) ± √[-(-5)² - 4*2*3]} / 2*2 = 0
5 ± √(25 - 24) / 4 = 0
x = (5 ± 1) / 4
x = 6/4 or 4/4
x = 3/2 or 1
2007-01-29 05:56:03 · answer #1 · answered by Brenmore 5 · 0⤊ 0⤋
The real roots are 1 and 3/2.
2007-01-29 05:32:02 · answer #2 · answered by platinto 2 · 0⤊ 0⤋
2x^2 - 5x + 3 =0 factors by inspection to
(2x )(x ) factors of 2x^2
(2x - )(x - ) both negatvie because middle term is negative
and final term is positive
(2x - 3)(x - 1) =0 ==>
factors of 3 that when multiplied by 2 and 1 add
up to 5. Next set each factor = 0
2x - 3 = 0 or x - 1 = 0 ==>
solve each equation for x
2x = 3 or x = 1 ==>
x = 3/2 or x = 1 the two possible answers.
none of your 4 choices has these two anwsers so
the answer is none of the available roots unless you say the positive root of 3) and the positive root of 4)
2007-01-29 06:16:39 · answer #3 · answered by bjs820 2 · 0⤊ 0⤋
roots are 1 and 3/2
2007-01-29 05:30:46 · answer #4 · answered by maussy 7 · 0⤊ 0⤋
None of the above, because it has only positive roots. The roots are 1 and 3/2.
2007-01-29 05:32:23 · answer #5 · answered by Anonymous · 0⤊ 0⤋