IF YOU MEAN
Multiply, 4xy^3*2x^(2y)*5xy^2?
How did I get this
Use the rules for Multiplying exponents or powers and break it down.
http://oakroadsystems.com/math/expolaws.htm#Multiply
4xy^3*2x^(2y)*5xy^2
4*2*5 = 40
xy^3 + xy^2 = xy^5
x^(2y)
Put it back together.
40xy^5x^(2y)
4xy^3 . 2x^(2y). 5xy^2 = 40xy^5x^(2y)
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IF YOU MEAN
4xy^3 . 2x^2*y . 5xy^2
Break it down and Use the rules for Multiplying exponents.
4*2*5 = 40
xy^3 + xy^2 = xy^5
x^2*y
Put it back together
40xy^5x^2*y
4xy^3*2x^2*y*5xy^2 = 40xy^5x^2*y
2007-01-29 03:15:30
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answer #1
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answered by Anonymous
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Multiply coefficients first. Then multiply variables (add the exponents)
(4*2*5) (x^(1+2+1)) (y^(3+1+2)) = 40 x^4 y^6
2007-01-29 03:21:17
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answer #2
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answered by Anonymous
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There is only multiplication within a term.
Multiply the numbers 4*2*5 (40)
Multiply the x*x^2**x (x^4)
Multiply y^3*y*y2(y^6)
40x^4y^6
2007-01-29 03:19:17
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answer #3
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answered by Ron H 6
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that's no longer clean that u have taken sq., cube or straightforward multiplication. So I even have given answer in 2 way. 4xy3 * 2x2y * 5xy2 =4xy^3 * 2x^2y * 5xy^2 or 12xy*4xy*10xy? =40x^4*y^6 or 480x^3*y^3 or 80x^3*y^6 whether that's 2x.2y(no sq.)
2016-11-28 02:52:44
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answer #4
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answered by Anonymous
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40 x^4 y^6
2007-01-29 03:19:32
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answer #5
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answered by Dave aka Spider Monkey 7
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Just list out all the terms:
4.x.y.y.y.2.x.x.y.5.x.y.y
group them:
4.2.5.x.x.x.x.y.y.y.y.y.y
simplify:
40.x^4.y^6
2007-01-29 03:17:10
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answer #6
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answered by Robert H 1
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68. 34 52 im kidding pay attention to the teacher,,and get off the computer and get back to your test
2007-01-29 03:14:53
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answer #7
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answered by ashton_35_kingsport 2
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40x^(2+2y)y^5
2007-01-29 03:16:38
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answer #8
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answered by JC 301186 3
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40x^4y^6
2007-01-29 03:19:21
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answer #9
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answered by prs1145 1
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