sinx=sinx/cosx
sinxcosx=sinx
sinxcosx-sinx=0
sinx(cosx-1)=0
sinx=0, x=0
cosx=1, x=0 also since you said x is small
2007-01-29 00:33:43
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answer #1
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answered by Professor Maddie 4
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When x=0, sin x=0 and tan x =0 , so sin x =tan x , exactly equal in this case. When x is small, the sin x and tan x are approximately equal, each of them equal to x (in radians), actually x being the first term in the series expansion of sin x as well as tan x. For x small , the higher order terms are negligible as compared to x.
2007-01-29 07:37:04
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answer #2
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answered by Anonymous
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x=0
2007-02-01 11:04:00
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answer #3
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answered by SUDESH S 1
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tanx = sin x / cos x. When x is very small, cos x is almost 1; so sinx = tan x is more true the more x nears 0
2007-01-30 12:54:13
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answer #4
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answered by Anonymous
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x is x only in place of sin we are changing tan
2007-01-29 07:41:18
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answer #5
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answered by hari krishna 2
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tan X=(sin x/cos X)
where x is small cosider zero
therefore cos x=1
tan x=sin x
2007-01-29 08:51:23
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answer #6
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answered by Anonymous
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sin x = opposite/hypotenuse
tan x = adjacent/hypotenuse
if x is very small then hypoenuse = adjacent almost
qed
2007-01-29 07:38:12
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answer #7
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answered by Anonymous
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as tanx=sinx/cosx
and when x is very small i.e. x tends to zero then the denominator cosx tends to 1.
so the numerator sinx=tanx
2007-01-29 13:46:36
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answer #8
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answered by mundane gal 2
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tan(x) = sin(x)/cos(x)
if x -->0, cos(x)-->1, so tan(x) --> sin(x)/1 = sin(x)
2007-01-29 07:38:51
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answer #9
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answered by mjatthebeeb 3
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b cos
lim sinx=x
when x------>0
and also lim tanx=x
when x----->0
so lim sinx=tanx
when x---->0
2007-01-29 07:32:26
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answer #10
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answered by miinii 3
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