Molarity = moles of solute / liter of solution
**to find the moles of solute, mass/molecular weight
Normality=number of gram equivalents of solute/liter of solution
*number of gram equivalents of solute = mass in grams of solute/ equivalent weight
*equivalent weight= molar mass/ number of H/OH
2007-01-28 22:02:16
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answer #1
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answered by ~steffi~ 2
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Normality Formula
2016-09-30 23:34:12
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answer #2
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answered by heusel 4
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This Site Might Help You.
RE:
what is the formula of Molarity? and Normality?
2015-08-10 22:41:41
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answer #3
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answered by Neile 1
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Normality Calculation
2016-12-11 16:27:19
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answer #4
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answered by cavallo 4
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Molarity=moles of solute divided by liter of solution.
Normality=Grams divided by (equivalent weight times volume).
2007-01-28 19:19:29
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answer #5
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answered by Anonymous
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This excellent article covers all the important definitions:
http://en.wikipedia.org/wiki/Concentration
Molarity = wt in grams equivalent to molecular wt of solute/ total volume of solution
Normality = wt in grams equivalent to molecular wt of H+ or OH- ions / total volume of solution.
2007-01-28 19:30:03
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answer #6
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answered by gp4rts 7
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Molarity denoted by symbol M= n/volume of solution (in L)
here n= number of moles of solute dissolved.
you can calculate it as n=weight of solute given/molecular mass of solute.
Normality denoted by symbol N
N= Mass of solute dissolved/equivalent weight x volume of solution(in L)
equivalent weight=mass/basicity or acidicity*
* number of replaceable OH
2007-01-28 19:27:07
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answer #7
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answered by xyz123 1
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molarity = # of moles / volume
normality = contration multiplyied by # of equivalent
2014-07-10 23:44:29
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answer #8
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answered by Tiroyaone 1
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For the best answers, search on this site https://shorturl.im/awitu
mole fraction=No. of mole/total mole normality=wt. of substance/equivalent wt*volume(litre) molarity=wt. of substance/molecular wt*volume(litre) molality=wt. of substance/molecular wt*solvent(in Kg)
2016-04-08 12:02:09
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answer #9
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answered by Anonymous
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NORMALITY:mol.wt/grm.mol.wt intovolume in lit or in mlitres
2016-03-18 07:21:53
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answer #10
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answered by Anonymous
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