Help...maths algebraic problem, can u solve?

Question

A man travels from A to B at 4 km/h and from B to A at 6 km/h. The total journey takes 45 minutes. Find the distance travelled.

And...could you explain each step, please?

Answer 1

Lets assume distance between A and B is = x
From a to b distance traveled at constant speed i.e. 4 km/h
speed = distance /time
4 = x/t1 (t1 = time taken from A to B)
therefore x = 4t1 .............. equ 1
Similarly x = 6t2 (t2 = time taken from B to A) .............. equ 2
by equating both the equations we get 4t1 = 6t2
or t1 = 1.5 t2 ...............equ 3
Given - total time taken for to and fro traveling = 45 min
hence
t1+t2 = 45 ...............................................................equ 4
place the value of t1 from equ 3 in equ 4
we get
1.5t2 + t2 = 45
hence
t2 = 45/2.5 = 18 minutes = 18/60 hrs = 0.3 hrs
Put the value of t2 in equ 2
distance x = 6t2 = 6*0.3 = 1.8 Kms
Total distance traveled in to and fro journey = 2x
therefore total distance = 2*1.8 = 3.6 Kms
Ans = 3.6 Kms

Hope it will serve your purpose
I am Nitin, be a friend and be in touch, always available for your help.

Answer 2

1. Use the formula: Distance = Speed * Time, or D = ST.
2. Convert all times to hours, so the total journey = 3/4 hr.
3. Let D = distance from A to B.
4. Let T1 = time to travel from A to B.
5. Let T2 = time to travel from B to A.

Now, from A to B, we have: D = 4 * (T1),
and from B to A, we have: D = 6 * (T2).

From these equations we obtain: T1 = D/4 and T2 = D/6.

Adding, we get: T1 + T2 = D/4 + D/6 = 3/4
Multiplying through by 12 gives: 3D + 2D = 9
or, 5D = 9
Thus, D = 9/5 = 1.8 km,
which means his total distance travelled = 2 * 1.8 = 3.6 km.

Answer 3

call distance x. 4t1+6t2 = 2x, while t1+t2 = 3/4 (not 45).

we get 5t1 = 9/4, or t1 = 9/20 = 27 min. so x = 4*9/20 = 9/5 = 1.8 km. Therefore distance - 2x = 3.6 km.

Steve

Answer 4

lets define the distance from A to B as X
time to go one way is X/4 hours
time to go back is X/6 hours
total time is X/4+X/6 = 0.75 Hours
so X= 1.8 Km
total distance is 2X = 3.6 Km.

Answer 5

suppose distance is x Km
then from A to B he takes x/4 hrs and in return journey he takes x/6 hrs...
so x/4+4/6=45/60

5/12x=3/4
x=3/4*12/5

x=1.8 km

Answer 6

A -> B at 4km/h
B -> A at 6km/h

A -> B = B -> A = X

x km at 4km/h = x/4 hours
x km at 6km/h = x/6 hours

x/4 + x/6 = 0.75
6x + 4x = 18
10x = 18

x = 1.8

Total distance = 2x = 3.6km

Answer 7

like the former musician stated at the same time as requested "how do you get to Carnegie corridor: "practice, guy, practice." As you try to benefit algebra, do not attempt to apply shortcuts, except those you're taught. otherwise, you'll attempt to apply them the position they don't artwork, and also you'll both develop into at a loss for words or get the incorrect answer. The extra algebra you do, the added effective you receives. there is really no incorrect way.

Answer 8

From A to B:
v1=s1/t1
so.t1=s1/v1
=s1/4

From B to A:
v2=s2/t2
so,t2=s2/6


Given tht total time taken is 45/60=0.75 hr,

t1+t2=0.75

s1/4+s2/6=0.75
so,6s+4s=18
10s=18s=1.8km

Answer 9

distance=velocity times time
x=v.t
x=v1.t1
x=v2.t2

v1=4
v2=6
t1+t2=45

v1.t1=v2.t2
4 t1=6 t2
or

2t1=3 t2
3t1+3t2=135
3t1+2t1=135
5t1=135
t1=27

x=4*27
= 108 km.