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the formation of condensation on a cold glass of water will cause it to warm-up faster than it would otherwise. i'm looking for the final temperature. ignore the effect of the surrounding.

2007-01-28 17:56:15 · 2 answers · asked by NuRz 1 in Science & Mathematics Physics

2 answers

Liquids can not be compressed hence It will depend on surface area of glass won't it? I am not sure but we will require dimensions of glass

2007-01-28 18:53:42 · answer #1 · answered by Mihir Durve 3 · 0 0

Look up the heat of vaporization of water, which is also the heat of condensation. Call it Hv in cal/g. Now look up the heat capacity for glass, say cp_g in cal/g-deg C. Also need the heat capacity of water, cp_w. Let T1 and T2 be the start and end temps. They give T1 as 5 C. Then:

8g * Hv = (T2-5)*100*cp_g + (T2-5)*300*cp_w

Note this calc assumes the condensate forms at T2, so no correction is made for having to heat up the condensate.

Can of course also work in joules rather than calories. Just be sure the units for Hv and cp are consistent in weight and energy.

2007-01-29 04:27:14 · answer #2 · answered by SAN 5 · 0 0

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