English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

simple, I know...
just answer please ! :)

2007-01-28 17:35:54 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

Assuming you mean (x^2) + a and not x^(2+a), just take the derivative of each term with respect to x. The derivative of x^2 is just 2x, following the rule that the derivative of x^p for some power "p" is p*x^(p-1). And assuming "a" is a constant, the derivative of that is zero. So the derivative of x^2 + a is 2x + 0, or simply 2x.

2007-01-28 17:45:29 · answer #1 · answered by Anonymous · 0 0

for x^n , derivative is n*x^(n-1)..so for x^2 derivative is 2*x(2-1)= 2*x^1=2x
for constant derivative is 0 , so for a derivative is 0

so derivative of x^2+a = 2x

2007-01-29 01:46:01 · answer #2 · answered by Pradeep Chelani 2 · 0 0

2*x all you have to do is multiply the function by the exponent and minus one from the exponent... so if you have the function f(x)= a*x^b the derivative is going to be a*b*x^(b-1). The a disappears because it is a constant and there is x to take the derivative. So the derivative to a with respect to x is just zero

2007-01-29 01:40:19 · answer #3 · answered by thexgodfatherx69 2 · 0 0

y = x^2+a

the derivative of x^2 =2x, The derivative of a =0

so dy/dx= 2x

2007-01-29 01:55:49 · answer #4 · answered by maussy 7 · 0 0

2x

2007-01-29 01:44:25 · answer #5 · answered by newlex 2 · 0 0

fedest.com, questions and answers