can someone please do the derrivative of y= ((x^4)/8) + (1/(4x^2))?

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2007-01-28 16:34:04 · 5 answers · asked by Robert 1 in Science & Mathematics ➔ Mathematics

y' = x^3/4 - 1/(2x^3)

2007-01-28 16:48:42 · answer #1 · answered by sahsjing 7 · 0⤊ 0⤋

4 * (x^3)/8 + 8x
= (x^3)/2 + 8x

2007-01-28 19:21:25 · answer #2 · answered by Pradeep Chelani 2 · 0⤊ 0⤋

x^3/4 -8x/16x^4
=x^3/4-1/x^3

2007-01-28 16:46:39 · answer #3 · answered by bruinfan 7 · 0⤊ 0⤋

derivative

1/8*4*x^3+

1/4*(-2)*1/x

=x^3/2+
(-1/(2x))

2007-01-28 16:50:53 · answer #4 · answered by iyiogrenci 6 · 0⤊ 0⤋

dy/dx =(1/8)*(4x^3)-8x^-3
=(x^3)/2 - 8x^(-3)

2007-01-29 01:13:21 · answer #5 · answered by laminewton 2 · 0⤊ 0⤋