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I am a straight A making 8th grade student and I am struggling with inequalities so please help. If you know one and not some just post the one(s) you know with the number.Thank You so much!!!!!!!!!!

2007-01-28 16:31:05 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

no like x>-3 or x>1 type answers

2007-01-28 16:40:06 · update #1

5 answers

1.x-6-2(x+8)<0
x-6-2x-16<0
-x-22<0
-x<22

x>-22


2.-6<-3x-6<6
add 6 to both sides
-6+6<-3x-6+6<6+6
0<-3x<12
divide by -3
0>x>-4

-4

3.-10<-2x+8<6
subtract 8 from each part
-18<-2x<-2
-9<-x<-1
9>x>1

1

4. 4(x-4)<-6+4x
4x-16<-6+4x
-16<-6
16>6
always true
x can be everything

5.-3(x-6)<2-3x
-3x+18<2-3x
18<2
false


6.x-1<3 and -4x<12
x-4<0 and -4x-12<0

x<4 and x>-3

the answer is
-3

2007-01-28 16:47:59 · answer #1 · answered by iyiogrenci 6 · 0 0

locate all zeros of f(x) = 2x^4 - 5x^3 +3x^2 + 4x - 6 Rational root theorem, guy made branch and in keeping with risk some factoring: by skill of inspection, x = -a million is a root: 2 + 5 + 3 - 4 - 6 = 0 Divide out the element (x+a million) by skill of guy made OR long-branch: 2x^4 - 5x^3 +3x^2 + 4x - 6 = (x+a million) * (2x^3 - 7x^2 + 10x - 6) For the cubic, a risk rational roots: components of -6 = +/- a million, 2, 3, 6 components of two = +/- a million, 2 a risk zeros: +/- a million, 2, 3, 6, a million/2, 3/2 by skill of inspection neither a million or -a million artwork. getting in the process the record with guy made branch we discover that 3/2 works: 2x^4 - 5x^3 +3x^2 + 4x - 6 = (x+a million) * (2x - 3) * (x^2 - 2x + 2) The quadratic element does no longer element. looking this is roots will require ending up the sq. or the quadratic formula: ALL zeros of f(x): -a million, 3/2, a million +/- i =======================================... After seeing something of the JUNK responses, i could no longer help myself: x^2 - 2x + 2 = 0 x^2 - 2x + a million = -a million (x - a million)^2 = -a million x - a million = +/- i x = a million +/- i

2016-09-28 03:23:23 · answer #2 · answered by ? 4 · 0 0

1. x-6-2x-16<0 -3x-24<0 -3x<24....x>-24
2. -6<-3x-6<6 0<-3x<12 0>x>-4
3. -10<-2x+8<6 -18<-2x<-2 9>x>1
4. 4x-16<-6+4x 0<10 x=any value
5. -3x+18<2-3x 0<-16 no solution
6. x-1<3 x<4
7. -4x<12 x>-3

2007-01-28 16:42:37 · answer #3 · answered by bruinfan 7 · 0 0

are you wanting like true or false answers?

2007-01-28 16:37:21 · answer #4 · answered by Robert 1 · 0 0

srry buddy your on your own

2007-01-28 16:37:11 · answer #5 · answered by MaoAce7 1 · 0 0

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