using congruence?

Question

Prove using congruence: m, m+1, m+2 are three consecutive integers, where m is an integer.
Q- Prove that the product of three consecutive integers is divisible by 6

Answer 1

m, m+1, m+2

product=m*( m+1)*( m+2)

=m^3+3m^2+2m

=0 mod 6

Answer 2

Any three consecutive numbers must contain one divisible by 3 and at least one even number. Therefore, the product of the three numbers must be divisible by 6.