its from a worksheet... thanks in advance ♥
the amount of air resistance acting on an object depends on the object's...
a) size and shape
b) mass and weight
c) density and mass
d) none of the above
2007-01-28 16:02:25 · 9 answers · asked by that one girl from that one band 3 in Science & Mathematics ➔ Physics
It is A. Think about it when you drop a piece of paper in the air, it slowly floats down to the ground due to air resistance. When you crumble it up it drops a lot faster, not changing its mass, just its shape.
2007-01-28 16:07:39 · answer #1 · answered by Mike 2 · 1⤊ 0⤋
The answer is A. Size and shape. This can be proved by holding a sheet by all four corners and letting the wind blow against it. Vary the sizes and shapes that it is in, fold it, roll it in a ball, change its shape and size.
Every change will result in a different amount of wind resistance yet the mass, or density always remains the same because it is the same object. Therefore size and shape are the primary factors influencing air resistance.
2007-01-28 16:10:03 · answer #2 · answered by Curious 1 2 · 1⤊ 0⤋
Think about what is going on with air resistance. Air molecules act to slow down an object in motion by friction. Therefore how much air encounters the object, and how much with respect to the area of the object are critical. Those translate to size and shape.
2007-01-28 16:08:51 · answer #3 · answered by Jerry P 6 · 1⤊ 0⤋
A... the more area for the air to hit, the more resistance.
same with shape, a circular object gets more resistance than lets say a pointy one
2007-01-28 16:05:45 · answer #4 · answered by bravestdawg101 3 · 1⤊ 0⤋
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2016-10-16 06:01:34 · answer #5 · answered by Anonymous · 0⤊ 0⤋
A) Size and shape
The more surface area that the air hits, the more resistance there is.
2007-01-28 16:06:38 · answer #6 · answered by King Ebeneezer 3 · 1⤊ 0⤋
size and shape
2007-01-28 16:07:24 · answer #7 · answered by Upo77 1 · 1⤊ 0⤋
a
2007-01-28 16:06:14 · answer #8 · answered by sk33t3r 3 · 1⤊ 0⤋
a.) size and shape
2007-01-28 16:06:51 · answer #9 · answered by webshotbmant 1 · 1⤊ 0⤋