Any help is greatly appreciated.
"A person purchased 5k+2 items for the cost of 35k^2+29k+6. Find the average cost per item of this purchase."
2007-01-28 16:01:31 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
division problem
(35k^2+29k+6) / 5k+2
-------------7k + 3
5k + 2 | 35k^2 + 29k + 6
----------35k^2 + 14k
_____________15k + 6
---------------------15k +6
answer
7k+3
2007-01-28 16:09:50 · answer #1 · answered by Bill F 6 · 0⤊ 0⤋
The average cost per item is just the total cost divided by the number of items. So it's (35k^2+29k+6)/(5k+2).
Notice though that you can factor (35k^2+29k+6) into (5k + 2)(7k + 3). So a (5k+2) cancels from the top and bottom, leaving you with 7k+3.
2007-01-28 16:13:59 · answer #2 · answered by Anonymous · 0⤊ 0⤋
You find the average cost by dividing the whole cost by the amount purchased
(35k^2+29k+6)/(5k+2)
the first thing that I tried was to factor the numerator using the denominator as a hint
(5k+2)(7k+3)=35K^2+15K+14K+6 = 35k^2+29k+6
this worked so I knew that I could divide by 5k+2
The average cost per item is 7k+3
I hope this helps
2007-01-28 16:13:56 · answer #3 · answered by tval_friedly 2 · 0⤊ 0⤋
average cost
= [35k^2+29k+6] / [5k+2]
2007-01-28 16:11:02 · answer #4 · answered by iyiogrenci 6 · 0⤊ 0⤋
7k+3
2007-01-28 16:45:58 · answer #5 · answered by MaoAce7 1 · 0⤊ 0⤋