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1) Does anyone know how to find the period of a Cos graph that is drawn out for you?

2) Does anyone know how to draw on a graph y=3sin(2/3+-pi/3) and can go in depth on how you did it?

3) Arccos (-square root of 2/2)

4) Arctan (square root of 3/2 + cos(pi/6)

5) Tan [Arccos (-square root of 3/2) - Arccos (square root of 3/2)

2007-01-28 14:28:49 · 1 answers · asked by joli334 3 in Education & Reference Homework Help

I forgot to add if you know how, please email me at jspellow@winonacotter.org or add me on MSN at joli334@yahoo.com and explain this to me.

2007-01-28 14:29:33 · update #1

1 answers

1. The period is the amount of x-axis between two rising crossings of that axis.
2. There being no x in the formula, the graph consists of a single horizontal line. The sine function can be evaluated, and the y intercept thus located.
3. The angle is 45 degrees, and it will lie in the second quadrant.
4. The individual angles can be figured; both relate to 30-60-90 right triangles. Draw them on graph paper, and see how the subtraction is done geometrically. It appears that a rotation of axes will display the tangent.

2007-01-28 14:39:55 · answer #1 · answered by Anonymous · 0 0

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