http://i63.photobucket.com/albums/h133/sexiazztomboi/algebraII.jpg On this page I need help with the Questions 14 and 16
http://i63.photobucket.com/albums/h133/sexiazztomboi/algebra.jpg 26 and 28 I need help with the Questions
2007-01-28 14:17:51 · 2 answers · asked by hotttlikeeefirrrrrre 1 in Science & Mathematics ➔ Mathematics
the links dont work...write out the problem for us to help you with
2007-01-29 15:18:49 · answer #1 · answered by Veer 3 · 0⤊ 2⤋
[a^2]^3 powers are higher =a^6 [ab^2]^4 powers are accelerated in each and every time period =a^4b^8 =[a^2b^5]^-2 =a^-4b^-10=a million/(a^4b^10) Your disaster [4 x^3n-a million y^2n-7]^3 4 has index a million so a million*3=3 4 would properly be raised to index 3=4^3 =sixty 4 (x^3n-a million) index 3n-a million will be multiplies by3 = 3n-3 and index 2n-7multiplied by technique of technique of three = 6n-21 =sixty 4 x^(9n-3) y^(6n-21)
2016-12-03 04:21:19 · answer #2 · answered by ? 4 · 0⤊ 0⤋