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For the following assume the relationship can be expressed as a Linear Equation in two variables. Use the given information to determine the equation and express the equation in Standard Form.

A company produces Fiberglass Shower Stalls, it can produce 10 stalls for $2015, and 15 stalls for $3015. Let 'y' be the cost and 'x' the number of stalls.

2007-01-28 14:15:54 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

This is a good example of the practical application of slopes and linear equation.

From your data, which is actually like 2 coordinate points, you can find the slope of the line. I am sure you know how to find it. The slope is 200.

Then to find the equation of the line just plug in any of the data points given to find the intercept. The intercept is 15 .

But, you need the STANDARD form not slope-intercept form so your final answer is

200x - y +15 = 0

2007-01-28 14:27:03 · answer #1 · answered by Aldo 5 · 0 0

We have two points (10, 2015) and (15,3015)
The slope = (3015-2015)/(15-10) = 200
So equation is y = 200x + b
2015 = 200(10) +b
2015-2000 - 15 = b
So equation is y = 200x +15

2007-01-28 14:24:51 · answer #2 · answered by ironduke8159 7 · 0 1

right here are issues excerpted from my own Calculus direction (dipping into linear algebra). i'm hoping those are applicable. #a million: Write out the two residences of a linear transformation. (trace key words: [a million] matrix, [2] vector area) #2: come across the linked matrix for each of right here changes. (notice: Coordinate notation has been used for spacing reasons; to calculate, you are able to convert the inquiries to column vectors.) _a. L: (a million, a million) --> 5; (a million, 0) --> 6 _b. L: (a million, a million, 0) --> (5, 2); (a million, 0, a million) --> (6, 2); (0, a million, a million) --> (a million, 0) _c. L: (cos(x), sin(x)) --> (a million, 0); (-sin(x), cos(x)) --> (0, a million) #3: supply the formulae for (a) scaling and (b) rotation matrices in variable words. the two ideas could exist in 2-dimensional area. #4: (a) clarify the magnitude of eigenvectors in diagonalization. (b) What are "imaginary" eigenvectors? (c) If neither a real eigenvector nor a pair of "imaginary" eigenvectors exists, can diagonalization nonetheless be performed? How? i don't be responsive to what situation of query you mandatory, yet those 4 hit the severe factors of my direction. wish this has helped. Cheers. lotrsbggamer significant notice: This answer bargains with actual "linear equations" in terms of linear algebra. If that isn't useful, I ask for forgiveness; I unquestionably have spoke back the query in accordance to my expertise of the words used.

2016-12-17 04:47:14 · answer #3 · answered by ? 3 · 0 0

you have two points (x, y) : (10, 2015) and (15, 3015)
m = 1000/5 = 200
y = 200x + b
2015 = 200*10 + b => b = 15

so y = 200x + 15

2007-01-28 14:20:05 · answer #4 · answered by Anonymous · 0 1

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