ok another problem, (25x^3/4)/5x^(4/5)?

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ok another problem, (25x^3/4)/5x^(4/5)?

2007-01-28 14:01:06 · 2 answers · asked by pokeralchemist 2 in Science & Mathematics ➔ Mathematics

2 answers

(25x^3/4)/5x^(4/5)
=(5x^3/4) / x^4/5
=5x^-1/20
=5/x^1/20

2007-01-28 14:12:56 · answer #1 · answered by A 150 Days Of Flood 4 · 0⤊ 0⤋

Your main issue is dividing x^3/4 by x^4/5. The exponent on x in the denominator is subtracted from the exponent on x in the numerator. Find a common denominator for these fractions and subtract them. 25 divided by 5 is pretty easy. Hint: my guess is that the common denominator is really close to 20.

2007-01-28 14:19:05 · answer #2 · answered by LJMan 2 · 0⤊ 0⤋