(x-10)(x+2)=0
x=10, x=-2
2007-01-28 13:42:57
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answer #1
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answered by CBM79 2
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(x+2)(x-10)
so X=-2 , X=10
2007-01-28 13:45:54
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answer #2
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answered by khaled s 1
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x= -2, 10 or (x-10)(x+2)=0
2007-01-28 13:44:05
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answer #3
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answered by Anonymous
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x^2 - 8x - 20 = 0
(x-10)(x+2) = 0
x-10 = 0: x = 10
x + 2 = 0: x = -2
Answer: x=10, x = -2
2007-01-28 13:43:05
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answer #4
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answered by Bill F 6
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The answer is
x = -2 OR x = 10
Because X^2-8x-20 Factors, resulting in (X-10)(X+2), which are your two 'solutions' to the problem, simply reversing the sign to finalize them.
2007-01-28 13:46:36
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answer #5
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answered by Anonymous
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x^2-8x-20=0
(x-10)(x+2) = 0
x=10 and x = -2
2007-01-28 13:43:10
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answer #6
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answered by ironduke8159 7
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(x-10)(x+2)=0
x=10 or x= -2
2007-01-28 13:47:57
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answer #7
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answered by Anonymous
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x = 4*(1+-i)
2007-01-28 13:43:06
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answer #8
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answered by geek31459 2
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x= -2 or x=10
Use the quadratic equation, and plug in values, or buy a TI-89.
2007-01-28 13:44:03
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answer #9
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answered by Anonymous
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i'm not sure if you're solving for x....
2007-01-28 13:46:34
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answer #10
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answered by nyadastar 2
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