can anyone explain to me how to solve this problem and the answer please?
[ (x^1/2y^-3/2) / (y^-1/2) ] ^ -2
(25x^3/4) / (5x^4/5)
2007-01-28 13:07:08 · 4 answers · asked by pokeralchemist 2 in Science & Mathematics ➔ Mathematics
[(x^1/2y^-3/2) / (y^-1/2)]^-2
Negative exponents mean reciprocals. (x^-2 = 1/x^2)
Fractional exponents mean roots. (x^3/2 = sqrt(x^3))
[(sqrt(x)sqrt(y^-3)) / sqrt(y^-1)]^-2
1/[sqrt(x)sqrt(1/y^3) / sqrt(1/y)]^2
(25x^3/4) / (5x^4/5)
= 25x^3/4 * 5/5x^4
= 5/4 * 5/x
= 25/4x
Now where you go with any of this is a mystery.
2007-01-28 13:32:36 · answer #1 · answered by Tim P. 5 · 0⤊ 0⤋
Holy crap. o.O
I'd try and help, but math isn't exactly my best subject to I'd better not. xD
2007-01-28 21:15:18 · answer #2 · answered by Anonymous · 0⤊ 1⤋
holy moly that looks super hard
2007-01-28 21:12:16 · answer #3 · answered by goldfish1679 3 · 0⤊ 1⤋
this makes no sense, better restate yer problem, buddy
2007-01-28 21:11:08 · answer #4 · answered by hendrik k 2 · 0⤊ 1⤋