Does this limit exist?
2007-01-28 12:48:39 · 4 answers · asked by joe s 1 in Science & Mathematics ➔ Mathematics
the function is [2004+(2003/2)+(2003/2n)]
2007-01-28 12:54:20 · update #1
DOES IT EXIST! I DONT CARE WHAT THE LIMIT IS!!!
2007-01-28 13:01:16 · update #2
The limit of [2004+(2003/2)+(2003/2n)] as n goes to infinity is 2004+(2003/2) = 3005.5, since the 2003/2n term goes to 0, but the others (since they do not involve n) remain constant.
2007-01-28 12:59:17 · answer #1 · answered by Phineas Bogg 6 · 0⤊ 0⤋
Yes, as n get's larger the last term goes to zero. A number divided by infinity is zero so your answer is:
2004+2003/2
2007-01-28 20:57:26 · answer #2 · answered by LGuard332 2 · 0⤊ 0⤋
Where's your variable?
In any case, you seem to multiplying infinity with a constant. Note that anything inside the [ ] as you wrote is just a constant.
Thus a constant multiplied by an infinity is another infinity.
Maybe you copied wrong?!?
Ok, I see your correction. And yes the limit EXISTS.
2007-01-28 20:55:24 · answer #3 · answered by Aldo 5 · 0⤊ 0⤋
I'm going to assume you mean lim{n->inf} (c-n)/n = lim {n->inf} c/n - 1 = -1.
2007-01-28 20:53:22 · answer #4 · answered by geek31459 2 · 0⤊ 0⤋