Jeanneine and two of her friends were hired to rake leaves by a neighbor. The house has a backyard and a frontyard that are the same size. The neighbor agreed to pay $60 for the entire job.
Jeanneine and one friend arrived to start at 9 a.m. By the time the third person came, the front yard was finished. All three of them finished the back yard together.
Each person must be paid based on the amount of time worked. How should the money be split between three friends?
Can someone please answer this for me? Also please include how you got the answer.
thanx
2007-01-28 10:13:14 · 5 answers · asked by Mariniac 3 in Home & Garden ➔ Garden & Landscape
split yard 30 for front 30 for back
2 split front 15-15
3 split back 10-10-10
1st two get $25 3rd gets $10
2007-01-28 10:19:37 · answer #1 · answered by Ides 2 · 1⤊ 0⤋
The assumption is being made that you are splitting the cost evenly for work completed in the front and back. However, when you calculate it as 1/2*a + 1/3*a = 60, a results in 12. (1/2a being the front, 1/3a being work completed in the back and "a" is a constant parrallel to the size of the yard/quantive to time). Thus each person would receive $24, $24 and $12 respectively. However, when you go to prove this, inputing hypothetical variables, the result is $25, $25 and $10.
The final determination is that this problem is a mathematical fallacy that cannot be proven, due to insufficient facts such as time completed or size of work performed.
2007-01-28 12:39:58 · answer #2 · answered by Surfer1973 1 · 0⤊ 0⤋
Jennifer & friend #1 split 1/2 of $60 or $15 each for the front yard.
The 3 friends then split 1/2 of $60 or $10 each for the back yard.
In total, Jennifer and friend #1 each get $25, the second friend gets $10. OK?
2007-01-28 10:21:20 · answer #3 · answered by cottagstan 5 · 0⤊ 0⤋
$30 for the front, split 2 ways.
$30 for the back, split 3 ways
2007-01-28 12:20:47 · answer #4 · answered by davidosterberg1 6 · 0⤊ 0⤋
Ides is right.
2007-01-28 10:22:10 · answer #5 · answered by Papa 7 · 0⤊ 0⤋