A constant net force of 410 N is applied upward to a stone that weighs 32 N. The upward force is applied ...?

Question

A constant net force of 410 N is applied upward to a stone that weighs 32 N. The upward force is applied through a distance of 2.0 m, and the stone is then released. To what height, from the point of release, will the stone rise?

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I'm having understanding how to solve it.
I have no idea what to do.

Answer 1

There are a couple different ways to interpret this question. The 410 could be one of two forces being applied to the object. Gravity might be the second force. I will work the problem assuming that the 410 Newtons has had the force of gravity already taken into account due to the use of the word "net".

Force times distance equals energy.
The energy imparted to the object is 2 meters times 410 Newtons resulting in 820 Joules.

Distance = energy divided by force.
Since the object has a weight of 32 Newtons and the original upward force resulted in 820 Joules of kinetic energy the height reached is 820/32=25.625 Meters above the height reached while under the effects of the upward force. If the point of release is where the upward force ceased being applied then that is the answer. If the point of release is when the upward force is first applied then the height is 2 meters higher or 27.625 meters.

Answer 2

artwork executed by technique of the stress(410N) on the stone=410*2=820 Joules improve contained in the flexibility of the stone= improve in P.E + Kinetic power ok received. = 32*2 +ok = sixty 4+ok Joules. Equating both: sixty 4+ok = 820 which substances ok = 756 Joules. assume the stone rises up a distance h meters from the area of launch to the utmost aspect the position it includes relax. Then the Kinetic power of the stone adjustments into its ability power. So: 32h =756 which substances h=756/32 =23.625 m answer