x^4d^6 - 9y^8z^4?

Question

Factor the difference of two squares-
remember the rule: a^2 - b^2 = (a+b)(a-b)

"{ ^ } = to the power of

Answer 1

x^4d^6 - 9y^8z^4 = (x^2 d^3 + 3 y^4 z^2)(x^2 d^3 - 3 y^4 z^2).

Live long and prosper.

Answer 2

x^4d^6 - 9y^8z^4
= (x^2d^3 - 3y^4z^2)(x^2d^3 + 3y^4z^2)

Answer 3

(x^2d^3)^2 - (3y^4z^2)^2
(x^2d^3 + 3y^4z^2) (x^2d^3 - 3y^4z^2)