What is the concentration of NH3 in household ammonia when 48.25 mL of 05246M HCL are needed to neutralize 22.00 mL of the ammonia solution?
What does the M stand for?
What is the end answer?
That's all I need to know so far.
2007-01-28 09:21:34 · 3 answers · asked by Basiate 5 in Science & Mathematics ➔ Chemistry
M = Molar = moles solute/liter of solution. So, 1.000 L of your HCl solution would contain 0.5246 moles of HCl (I'm guessing you just left off the decimal point).
For your problem, convert the volume of HCl into liters. Multiply that by the molarity to get moles of HCl. For this reaction, one mole of HCl will react with one mole of ammonia, so the moles of HCl = the moles of ammonia in your solution. Finally, divide the moles of ammonia by the volume of the ammonia in Liters, and you've got the molarity of the ammonia solution.
2007-01-28 09:45:51 · answer #1 · answered by hcbiochem 7 · 0⤊ 0⤋
M = Molar or molarity.
Here are some hints....
change the ml into liters (its easier to work with)
use the molecular weight of HCL (36.46)
2007-01-28 09:32:08 · answer #2 · answered by Fox_747 2 · 0⤊ 0⤋
M stands for Mole, a molecular quantity. If you don't know how to use Moles you need to go back to your chemistry notes.
05246 is a colossal amount. Are you sure that is correct?
2007-01-28 09:26:39 · answer #3 · answered by Anonymous · 0⤊ 1⤋