A total of 129 players entered a single elimination handball tourney. In the first round of play, the top seeded player received a bye and the remaining 128 players played in 64 matches. Thus 65 players entered the second round of play. How many matches must be played to determine the tournament champion?
2007-01-28 08:34:27 · 8 answers · asked by Soccer Chick 1 in Education & Reference ➔ Homework Help
This is a trick question, there is a very simple way to solve it. It only takes logic. If its single elimination then the only way a player can get out is by losing 1 match. And every match will result in one player being eliminated. So if every player, but the champion , were to be eliminated then 127 matches have to be played (one for every elimination).
2007-01-28 08:44:53 · answer #1 · answered by Salem E 2 · 0⤊ 0⤋
I dont see how you can have 65 players in the second round unless one of them gets a bye
So let's say it's: 64+32+16+8+4+2+1+1
2007-01-28 16:38:21 · answer #2 · answered by Anonymous · 1⤊ 0⤋
14
2007-01-28 16:39:25 · answer #3 · answered by Anonymous · 0⤊ 0⤋
33
2007-01-28 16:43:17 · answer #4 · answered by Joe 1 · 0⤊ 0⤋
33 matches because 65/2+=32.5 round up =33
2007-01-28 16:39:08 · answer #5 · answered by A question or two... 3 · 0⤊ 0⤋
accourding to my calculations it would take 129 matches to get a champion.
2007-01-28 16:42:10 · answer #6 · answered by airshev 1 · 0⤊ 0⤋
forget the homework man, just watch some tv. the only thing math will do for you is give you a headache
2007-01-28 16:38:44 · answer #7 · answered by Anonymous · 0⤊ 0⤋
go to math nerds they will help u
2007-01-28 17:15:45 · answer #8 · answered by Anonymous · 0⤊ 0⤋