the sum to infinity of a geometric series is 5 and the first term is 2. find the common ratio of the series?

Answer 1

Infinity........(unless your Buzz light year)can not be defined in this way....get an education if you want to be a smart git...sad sad..sad

Answer 2

The sum to infinity of a geometric series is a/(1-r) where a is the first term and r is the common ration. In this case

2/(1-r) = 5
(1-r) = 2/5 = 0/4

Therefore r = 0.6

Try it out and you will find that the sum of terms is 4.999976 after 25 terms.

Answer 3

sum (infinity) = a/(1 - r) where a is first term and r is the common ratio.
Thus in this case 5 = 2 / (1 -r)
5(1 - r) = 2
5 - 5r = 2
5 = 2 + 5r
5r = 3
r = 3/5

Answer 4

S= a/(1-r)

5=2/(1-r)

take the recriprocal of both sides

1/5 = (1-r)/2

2/5 = 1-r

r = 1-2/5 = 3/5

Answer 5

sum to infinity is,

a / (1-r) , where a=2 here, common ratio = r.

so, 2 / (1-r) = 5, so,

2 = 5(1-r), so, -3=-5r, so, r=3/5

Answer 6

sum to infinityS=a/(1-r)
1-r=a/S
r=1-a/S
=S/S-a/S=(S-a)/S...(1)
where a= 1st term and
r=the common ratio

hence,from (1),
r=(5-2)/5=3/5

therefore,the common ratio
is 3/5

i hope that this helps

Answer 7

You REALY need to get out more!