A constant net force of 410 N is applied upward to a stone that weighs 32 N. The upward force is applied through a distance of 2.0 m, and the stone is then released. To what height, from the point of release, will the stone rise?
Please help me with this problem.
I'm having trouble solving it.
2007-01-28 07:17:02 · 3 answers · asked by swimmertommy 1 in Science & Mathematics ➔ Physics
The energy of propulsion upwards at the point of release is
Applied force X Distance traveled, which is
410 X 2 = 820 Joules
This energy will then propel the stone to a vertical height of
820 / 32 = 25.625m (from the point of release)
Note: Energy is Force X Distance, so that
Distance = Energy / Force
Also know that weight is a type of force.
2007-01-28 07:34:47 · answer #1 · answered by agboola f 2 · 1⤊ 0⤋
Work done by the force(410N) on the stone=410*2=820 Joules
Increase in the energy of the stone= Increase in P.E + Kinetic energy K gained. = 32*2 +K = 64+K Joules.
Equating the two: 64+K = 820 which gives K = 756 Joules.
Suppose the stone rises up a distance h meters from the position of release to the highest point where it comes to rest. Then the Kinetic energy of the stone changes into its Potential Energy. So: 32h =756
which gives h=756/32 =23.625 m Answer
2007-01-28 15:51:04 · answer #2 · answered by Anonymous · 0⤊ 0⤋
6560 watts
2007-01-28 15:22:58 · answer #3 · answered by Anonymous · 0⤊ 1⤋