how would you write the following equations in standard form....please show how you got your answer because i would like to understand how to solve it.thank you.
1. 4x-y-7=0
2.-4x+5y+16 =0
2007-01-28 06:34:47 · 4 answers · asked by jessesbabe 1 in Science & Mathematics ➔ Mathematics
general form = standard form
Linear equations
ax + by = c
4x - y - 7 = 0
4x - y - 7 + 7 = 0 + 7
4x - y = 7
The standard form is 4x - y = 7
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4x + 6y + 16 = 0
4x + 6y + 16 - 16 = 0 - 16
4x + 6y = - 16
The standform is 4x + 6y = - 16
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2007-01-28 07:20:33 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
THe equation for standard form is: Ax+By=C
1. 4x-y=7 Because you add 7 to both sides
2. -4x+5y=-16 Because you subtract 16 from both sides
2007-01-28 06:40:02 · answer #2 · answered by buttercup 3 · 0⤊ 1⤋
i wager your speaking about a line dealing with those 2 factors? First locate the slope, upward push over run. You bypass 3 up and a pair of to the right, so the slope is 3/2. Use factor slope formulation, y-y1=m(x-x1) y-a million=3/2(x-a million) y= 3/2 x -a million/2
2016-10-16 05:33:52 · answer #3 · answered by rotchford 4 · 0⤊ 0⤋
4x-y=7
4x-5y=16
You need to put x and y on one side and the constant on the other side. The coefficient of x must be positive.
2007-01-28 06:38:28 · answer #4 · answered by Professor Maddie 4 · 0⤊ 0⤋