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Given: triangle PQR aith altitude QA, angle bisector QB, and median QM, with B between A and M.

Prove: QA < QB< QM
(triangle drawn is an acute triangle) sorry I cant draw the picture

Q on top
P A B M R across the bottom (longest end on the right)
SHOULD BE 10 STEPS AND I AM SO LOST

2007-01-28 05:50:34 · 1 answers · asked by hoopmaster1 1 in Science & Mathematics Mathematics

1 answers

It is clear that QA QB M is closer from QR because the triangles QPM and QRM have same area. since A is closer from QP that implies that B is between A and M so AB

2007-01-28 06:13:17 · answer #1 · answered by gianlino 7 · 0 0

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