How can I make an electromagnet strong enough to lift a fridge?

Question

I'm not experimenting this, but I just need to know how many batteries I need or how many wraps of wire I need.

Answer 1

It depends on the weight of the frig and the exact design of the coil, but you need several hundred windings of fine wire and quite a few batteries (or a strong car battery or two) to lift the unit, then the batters won't last too long.

Answer 2

A strong current is not needed, what you need is a high voltage. If you could get an alternating electrical source, say, the wall, and run it through a large step-up transformer (increases voltage, reduces amperage) and put an appropriate resistor on the circuit if needed (500 to 800 ohm with a 25 watt rating should be good for wall power for this), you could get the voltage up pretty high. I'd say you'd need a few thousand volts of electricity, and if the amperage to the electromagnet is below 5 amps, you could probably get away with using 20-gauge wire (better be a fuse on that circuit, though). I'd say the electromagnet could be 4 inches in diameter, about 6 in length, and wrap the wire down the length of the electromagnet about 10 times. With 5000 volts going through it, all of this should be a little overkill, depending on how much magnetic metal is in the fridge (no calculations for this, sorry). Just get the most conductive metal for the core as possible, if you can, pure iron.

Answer 3

a high current needs to be passed..number of turns in coil should be more too